2x+4+3x+6+x^2-9x-844=180

Solution for 2x+4+3x+6+x^2-9x-844=180 equation:

2x+4+3x+6+x^2-9x-844=180

We move all terms to the left:

2x+4+3x+6+x^2-9x-844-(180)=0

We add all the numbers together, and all the variables

x^2-4x-1014=0

a = 1; b = -4; c = -1014;
Δ = b2-4ac
Δ = -42-4·1·(-1014)
Δ = 4072
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4072}=\sqrt{4*1018}=\sqrt{4}*\sqrt{1018}=2\sqrt{1018}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-2\sqrt{1018}}{2*1}=\frac{4-2\sqrt{1018}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+2\sqrt{1018}}{2*1}=\frac{4+2\sqrt{1018}}{2}
$